Monday, February 15, 2010

K equilibrium Lab

I do not understand the directions for the second post-lab calculation and analysis question. I graphed my data and it came to be linear. Then I drew a line of best fit. I do not understand how to determine the FeSCN2+ concentrations through the directions given in question 2.

I also think my numbers are messed up. For example, my results for data table 3 were 4.2x10^-4 M (FeSCN2+)eq, 5.8x10^-4 M (Fe3+)eq and .0016 M (SCN-)eq. When i solved for the K values in data table 3 with the equation K= Products/Reactants, my K value came around to 452. That seems a little off.....

Anyone have any suggestions or examples of what they think the correct data is?

-Mike

2 comments:

  1. First, from the line of best fit equation, you can determine the FeSCN2+ concentrations. Remember that your y=mx equation generated by the line of best fit is really the beer's law equation: A=ebc where A is y, "eb" is m, and c is x. Therefore, if you plug in your measured absorbence in for y, you can solve for x, which will be the FeSCN2+ equation.

    Also, double check your Fe3+ and SCN- concentrations; they don't seem correct. Remember, using the DILUTED concentrations, you must subtract the FeSCN2+ value to determine the final concentrations to plug into your K eq. That being said, I remember the K value being between 100 and 200, but obviously that is somewhat dependent on your data, and execution of the lab.

    Post if you have any more questions.

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  2. My Equation comes to be y=.0043x+.0022

    Does that Sound close?? The trendline is important to my success in the rest of the lab. If that is wrong then maybe i messed up earlier in the lab. I am getting my FeSCN2+ values to be around 5.87. Then when i find the Fe3+ equalibrium value, it comes out to be negative

    -Mike

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